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LastDayOfMonth(strMonth[, strYear])

Last updated May 07, 2002

author

Ryan Kime

Version: 1 | Requires: CF5 | Library: DateLib

Description:
LastDayOfMonth() takes your selected month as a number (1-12) and an optional given year (which is good for instances of a Leap Year). It returns a date object that you can then use DateFormat to get the appropriate format for the month, day, and year.

Return Values:
Returns a date object.

Example:

<cfset month = 2>
<cfset year = 2004>

last day of the month is: 
<cfoutput>#LastDayOfMonth(month, year)#</cfoutput>
<br>- or -<br>
last day of the month is: 
<cfoutput>#DateFormat(LastDayOfMonth(month, year), "dddd mmm dd, yyyy")#</cfoutput>

Parameters:

Name Description Required
strMonth Month you want to get the last day for, Yes
strYear Year for the specified month. Useful for leap years. The default is the current year. No

Full UDF Source:

/**
 * Returns a date object representing the last day of the given month.
 * 
 * @param strMonth      Month you want to get the last day for, (Required)
 * @param strYear      Year for the specified month.  Useful for leap years.  The default is the current year. (Optional)
 * @return Returns a date object. 
 * @author Ryan Kime (ryan.kime@somnio.com) 
 * @version 1, May 7, 2002 
 */
function LastDayOfMonth(strMonth) {
  var strYear=Year(Now());
  if (ArrayLen(Arguments) gt 1)
    strYear=Arguments[2];
  return DateAdd("d", -1, DateAdd("m", 1, CreateDate(strYear, strMonth, 1)));
}

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