LastDayOfMonth(strMonth[, strYear])
Last updated May 07, 2002
Version: 1 | Requires: CF5 | Library: DateLib
Description:
LastDayOfMonth() takes your selected month as a number (1-12) and an optional given year (which is good for instances of a Leap Year). It returns a date object that you can then use DateFormat to get the appropriate format for the month, day, and year.
Return Values:
Returns a date object.
Example:
<cfset month = 2>
<cfset year = 2004>
last day of the month is:
<cfoutput>#LastDayOfMonth(month, year)#</cfoutput>
<br>- or -<br>
last day of the month is:
<cfoutput>#DateFormat(LastDayOfMonth(month, year), "dddd mmm dd, yyyy")#</cfoutput>
Parameters:
Name | Description | Required |
---|---|---|
strMonth | Month you want to get the last day for, | Yes |
strYear | Year for the specified month. Useful for leap years. The default is the current year. | No |
Full UDF Source:
/**
* Returns a date object representing the last day of the given month.
*
* @param strMonth Month you want to get the last day for, (Required)
* @param strYear Year for the specified month. Useful for leap years. The default is the current year. (Optional)
* @return Returns a date object.
* @author Ryan Kime (ryan.kime@somnio.com)
* @version 1, May 7, 2002
*/
function LastDayOfMonth(strMonth) {
var strYear=Year(Now());
if (ArrayLen(Arguments) gt 1)
strYear=Arguments[2];
return DateAdd("d", -1, DateAdd("m", 1, CreateDate(strYear, strMonth, 1)));
}
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